What is the resistance of a resistor that dissipates 60 watts at 110 volts?

What is the resistance of a resistor that dissipates 60 watts at 110 volts?

• A. 151.66 ohms
• B. 201.66 ohms
• C. 110 ohms
• D. 120 ohms

Answer: (B)

To find the resistance of a resistor that dissipates 60 watts at 110 volts, you can use Ohm's Law and the power formula. The power (P) dissipated by a resistor is given by the formula: P = V^2 / R where P is the power in watts, V is the voltage in volts, and R is the resistance in ohms. Rearranging the formula to solve for resistance gives: R = V^2 / P Substituting the known values (V = 110 volts and P = 60 watts) into this formula: R = (110^2) / 60 Calculating this step-by-step: 1. First, calculate 110 squared, which is 12100. 2. Then divide that by 60. Doing the calculation gives: R = 12100 / 60 = 201.666... ohms This can be rounded to 201.66 ohms. Thus, the correct response indicating the resistance of the resistor that dissipates 60 watts at 110 volts is indeed approximately 201.66 ohms.

To find the resistance of a resistor that dissipates 60 watts at 110 volts, you can use Ohm's Law and the power formula. The power (P) dissipated by a resistor is given by the formula:

P = V^2 / R

where P is the power in watts, V is the voltage in volts, and R is the resistance in ohms. Rearranging the formula to solve for resistance gives:

R = V^2 / P

Substituting the known values (V = 110 volts and P = 60 watts) into this formula:

R = (110^2) / 60

Calculating this step-by-step:

1. First, calculate 110 squared, which is 12100.

2. Then divide that by 60.

Doing the calculation gives:

R = 12100 / 60 = 201.666... ohms

This can be rounded to 201.66 ohms.

Thus, the correct response indicating the resistance of the resistor that dissipates 60 watts at 110 volts is indeed approximately 201.66 ohms.