What is the peak-to-peak value if the RMS current is 35 amps?

What is the peak-to-peak value if the RMS current is 35 amps?

• A. 99 amps
• B. 70 amps
• C. 50 amps
• D. 120 amps

Answer: (A)

To find the peak-to-peak value from the RMS (Root Mean Square) current, you can use the relationship between these two measurements in an alternating current (AC) system. The RMS value is a way of expressing an equivalent direct current (DC) value to ensure that the heating effect, or power dissipated in a resistive load, is the same as that produced by a DC current. For a sinusoidal waveform, the peak (or maximum) value of the current is related to the RMS value by the formula: \[ \text{Peak} = \text{RMS} \times \sqrt{2} \] Substituting the RMS value into the formula gives: \[ \text{Peak} = 35 \, \text{amps} \times \sqrt{2} \approx 35 \times 1.414 = 49.9 \, \text{amps} \] The peak-to-peak value represents the total range of the waveform from its maximum positive value to its maximum negative value, which is twice the peak value: \[ \text{Peak-to-Peak} = 2 \times \text{Peak} \approx 2 \times 49.9 = 99

To find the peak-to-peak value from the RMS (Root Mean Square) current, you can use the relationship between these two measurements in an alternating current (AC) system. The RMS value is a way of expressing an equivalent direct current (DC) value to ensure that the heating effect, or power dissipated in a resistive load, is the same as that produced by a DC current.

For a sinusoidal waveform, the peak (or maximum) value of the current is related to the RMS value by the formula:

[ \text{Peak} = \text{RMS} \times \sqrt{2} ]

Substituting the RMS value into the formula gives:

[ \text{Peak} = 35 , \text{amps} \times \sqrt{2} \approx 35 \times 1.414 = 49.9 , \text{amps} ]

The peak-to-peak value represents the total range of the waveform from its maximum positive value to its maximum negative value, which is twice the peak value:

[ \text{Peak-to-Peak} = 2 \times \text{Peak} \approx 2 \times 49.9 = 99