What current will flow when a 10 µF capacitor is connected to a 240 V, 60 Hz supply?

What current will flow when a 10 µF capacitor is connected to a 240 V, 60 Hz supply?

• A. 0.9 A
• B. 1.2 A
• C. 0.0452 A
• D. 6.67 A

Answer: (A)

To determine the current flowing through a capacitor when connected to an AC supply, we can use the formula for capacitive reactance (Xc) and Ohm's law. The capacitive reactance is given by the formula: \[ X_c = \frac{1}{2 \pi f C} \] where: - \( f \) is the frequency in hertz (Hz), - \( C \) is the capacitance in farads (F). In this case, you are given a capacitance of 10 µF (which is 10 x 10^-6 F), a frequency of 60 Hz, and a voltage of 240 V. First, calculate the capacitive reactance: \[ f = 60 \, \text{Hz} \] \[ C = 10 \times 10^{-6} \, \text{F} \] Plugging in these values: \[ X_c = \frac{1}{2 \pi (60)(10 \times 10^{-6})} \] Calculating this gives: \[ X_c = \frac{1}{2 \pi (60) (10 \times 10^{-6})} = \frac{1}{0

To determine the current flowing through a capacitor when connected to an AC supply, we can use the formula for capacitive reactance (Xc) and Ohm's law. The capacitive reactance is given by the formula:

[ X_c = \frac{1}{2 \pi f C} ]

where:

• ( f ) is the frequency in hertz (Hz),

• ( C ) is the capacitance in farads (F).

In this case, you are given a capacitance of 10 µF (which is 10 x 10^-6 F), a frequency of 60 Hz, and a voltage of 240 V.

First, calculate the capacitive reactance:

[ f = 60 , \text{Hz} ]

[ C = 10 \times 10^{-6} , \text{F} ]

Plugging in these values:

[ X_c = \frac{1}{2 \pi (60)(10 \times 10^{-6})} ]

Calculating this gives:

[ X_c = \frac{1}{2 \pi (60) (10 \times 10^{-6})} = \frac{1}{0